Business Mathematics
Theory of Indices
CONTENTS:
1.
Formulas
2.
12 Selected Problems
3. Solutions to the Selected
Problems
Formulas
1 |
(am
× an) = |
a(m
+ n) |
2 |
(am
÷ an) = |
a(m
– n) |
3 |
(am)n
= |
amn |
4 |
(ab)m
= |
am
× bm |
5 |
a(−n)
= |
1/(an) |
6 |
n√a = |
a(1/n) |
7 |
a0 |
1 |
8 |
(abc...)m
= |
am
× bm × cm....... |
9 |
(a/b)m
= |
(am/bm) |
10 |
(am
× bm × cm...)n = |
amn
× bmn ×cmn |
11 |
n√am |
a(m/n) |
12 |
If
am = bm, |
a
= b |
13 |
If
am = an, |
m
= n |
Theory
of Indices
Selected
Problems
1 |
Express the following in single positive index: [x(−3/4)]5/3 |
2 |
Simplify [{(81)n.35 – 3(4n – 1).243}/92n.33]
– [4.3n/{3(n + 1) – 3n}] |
3 |
Show that (xb/xc)a × (xc/xa)b
× (xa/xb)c = 1 |
4 |
Show that (xm/xn)m+n−l × (xn/xl)n+l−m
× (xl/xm)l+m−n = 1 |
5 |
Show that [x(a^2 + b^2)/x−ab]a−b × [x(b^2 +
c^2)/x−bc]b−c × [x(c^2 + a^2)/x−ca]c−a
= 1 |
6 |
Show that [1/(1 + xb−a + xc−a)] + [1/(1 + xa−b +
xc−b)] + [1/(1 + xa−c + xb−c)] = 1 |
7 |
If 2x = 3y = 6z, show that z = (xy)/(x
+ y) |
8 |
If ax = by = cz and b2 =
ac, prove that (1/x) + (1/z) = (2/y) |
9 |
If xa = yb = (xy)c, show that ab = c(a
+ b) |
10 |
Show that x3 – 6x – 6 = 0, if x = 3√2 + 3√4 |
11 |
Solve (√5)(4x – 4) – 5(2x – 3) = 20 |
12 |
Solve 2(x + 3) + 2(x + 1) = 320 |
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